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| 15 Theory slides |
| 12 Exercises - Grade E - A |
| Each lesson is meant to take 1-2 classroom sessions |
Here are a few recommended readings before getting started with this lesson.
Kevin really wants to buy this cherry-red vintage bicycle. However, there is a major issue — he is just shy of the amount he needs! He talks with Uncle Dev, also a cyclist, about the issue. Uncle Dev offers Kevin a loan.
What is the percent of change from the price of the bicycle to the total amount that Kevin would pay his uncle?
There are several ways to solve percent problems. One of them is to write the percent as a ratio.
Kevin's uncle Dev works in a toy shop as a sales manager. He is responsible for monitoring the number of products sold. The following graph shows the number of toys sold by the shop in one day.
a=6, w=60
ba=b/6a/6
LHS⋅100=RHS⋅100
Calculate quotient
Rearrange equation
a=15, w=60
ba=b/15a/15
LHS⋅100=RHS⋅100
Calculate quotient
Rearrange equation
Solve the given percent proportion for the missing value. Note that a is part of the whole w and p% or 100p is the percent value.
Percent problems can also be solved by expressing the given situation as an equation. In that case, it is needed to write the percent as a decimal or as a fraction while solving the equation.
a is p percent of wis represented as the following equation.
Kids learn and grow through playing with toys that match their developmental stages. Uncle Dev is organizing toys at the shop according to age groups: infants, toddlers, and preschoolers. By category, the circle graph shows the percents of toddler and infant toys and number of preschool toys.
a=140, p=35
Write as a decimal
LHS/0.35=RHS/0.35
Rearrange equation
Calculate quotient
In the following applet, there is a percent equation representing the situation in which the part a is p percent of the whole w. Solve the equation for the missing value.
Sometimes it may be easier to evaluate the amount of change when it is expressed as a percent rather than as a number or a ratio. In that case the percent of change can be used.
Determine if the price of the item increases or decreases by looking at the difference between the new and original amounts.
Increase | New amount > Original amount |
Decrease | Original amount > New amount |
The change represents an increase since 15 is greater than 12.
Uncle Dev now wants to examine the percent of changes between visitors over the last two weeks. He prepares the following table that shows the number of people that visited the toy shop.
Notice that on the first week's Monday 75 person visited the toy shop but on the second week's Monday 81 people visited the shop. Since it shows an increase, the amount of change will be found by subtracting the original amount from the new amount.
Subtract terms
ba=b/3a/3
ba=b⋅4a⋅4
Convert to percent
Subtract terms
ba=b/9a/9
ba=b⋅10a⋅10
Convert to percent
In the following applet, the original and new amounts are given in a table. Find the percent of change based on these values. Also determine if this change is an increase or decrease. Round the answer to the nearest hundredth if necessary.
Sometimes the amount of error can be too big or too small to understand its effect clearly. Expressing the error as a percent is an alternative way to show the amount of the error.
The relative error is the ratio of the absolute error of a measurement to the exact value. The relative error tells how good a measurement is relative to the size of the object being measured. In other words, the relative error indicates how significant the absolute error is.
Relative Error =Exact ValueAbsolute Error
The Relative Error Formula can be rewritten by substituting the Absolute Error Formula.
Relative Error =Exact Value∣Measured Value−Exact Value∣
The percent error is the product between the relative error and 100%. It represents the relative error as a percentage.
Percent Error =Relative Error⋅100%
Consider, for example, a person fishing who expected to catch 480 crayfish. However, the number of crayfish they ultimately caught was 400. The percent error explains the degree of the mistake in the person's estimation.
Absolute Error | Relative Error | Percent Error |
---|---|---|
∣480−400∣=80 | 40080=0.2 | 0.2⋅100%=20% |
A customer falls in love with a toy for her daughter. It is called Luchador Teddy! Wait. It is missing a price. Uncle Dev estimates that it costs $12 and writes that. The customer goes to the register to buy it but sees she is about to be charged $13.50!
Calculate the amount of error. Then, find the relative error.
Absolute Error=1.50, Exact Value=13.50
Use a calculator
This lesson introduced how to find the percent of change using original and new amounts. The challenge presented at this chapter's start focuses on Kevin's tough decision. If he accepts the loan, he could get his dream bicycle. On the other hand, he could owe too large of an amount!
Find the amount of change between the price of the bicycle and the amount that Kevin would have to pay back. Then, apply the percent of change formula.
Amount of Change=8.40, Original Amount=84
ba=b/8.4a/8.4
ba=b⋅10a⋅10
Convert to percent
The two regather after Kevin found the percent change that his Uncle originally offered.
Uncle Dev is impressed, and embarrassed, by Kevin's math skills. Uncle Dev agrees to the counteroffer — realizing the overpayment.
The two can now take a cruise around town together!
Note that 15 hours represents 100 % of the battery. Since it is told that Mark's battery charge at 60 % now, we can calculate 60 % of 15 hours to see how many hours are left. Let's write this situation as an equation by using the percent equation. a= p % * w In this equation, a represents the part, p % represents the percent, and w represents the whole. Let's substitute our values into the percent equation. a= 60 % * 15 We will now solve this equation for the value of a.
Since Mark's trip will take 8 hours and his phone's battery will last 9 hours, we can say that yes, he can use his phone during the whole trip.
A medicine company conducted an experiment on 2500 voluntary people about the effects of a new medicine. The results show that of the 2500 people, 10 had a mild allergic reaction to this new medicine.
We are given that 10 out of the 2500 people that tried a new medicine had a mild allergic reaction. We want to find out what percent of the people had a mild allergic reaction. Let's start by drawing a bar diagram to represent the problem.
Next, we will write a percent proportion to find the percent. a/w=p/100 Note that a is the number of people with a mild allergic reaction and w is the total number of people. With this in mind, now substitute our values into the percent proportion. 10/2500=p/100 Note that we got an equation that we can solve for p. We will multiply both sides of the equation by 100 to get the percent value p alone.
We found that p=0.4. This means that 0.4 % of the people had a mild allergic reaction to the new medicine.
In the following figure, each grid is the same size.
We have been asked to establish the percent of the image is green. In other words, we want to know what percent of all of the squares are green squares. We will represent it by a percent equation. p % * b = a Here, b represents the whole which is the total number of squares and a is the part which is the total number of green squares.
As we can see, there are b=5 * 14 = 70 squares in total and a= 19 green squares in total. Now we can substitute these values into the percent equation and solve it for p.
We can conclude that about 27 % of the figure is green.
Mark uses a bar graph to display the results of a survey that asks several students to vote on a new candidate who will represent the school in a national dance festival.
However, Mark forgot to write the scale labels.
Note that the vertical axis is related to votes that each candidate received. However, there are no scale labels, except for the 0 one.
Without the scale we cannot tell how many votes each candidate received. However, we know that the number of lines each bar intersects tells how many portions of votes each candidate received. Let's count how many lines intersect the bars.
Next, let's add the found numbers to find how many overall portions of votes there were. 1+7+3+5+4 = 20 Notice that the most popular candidate, who is B, received 7 votes. Now that we also know the total portion of the votes, we can calculate the percent of the votes for the most popular candidate by using the percent equation. a=p % * w Recall that a represents the part which is the most popular candidate's portion of the votes, p is the percent, and w is the whole which represents the overall portions of the votes. With these in mind, let's substitute the obtained values into the percent equation.
We can conclude that the most popular candidate, who is candidate B, received 35 % of the votes.
Now, we assume that there are 240 votes total. We want to find how many votes are for candidate C. Recall the graph from the previous part in which we counted the number of tick lines each bar intersects.
From Part B we know that overall there are 20 portions of votes and 3 of them are votes for candidate C. Let's find the amount of percent of the votes that candidate C received by using the percent equation. a=p % * w ⇓ 3=p % * 20 Let's solve this equation!
We found that candidate C received the 15 % of the total number of votes. Now, let's calculate 15 % of 240.
This means that the candidate C received 36 votes.
The table shows the geometry scores of Mark in four tests. Mark needs to get 70% of the total test points to pass the course.
Test Score | Point Value |
---|---|
79% | 200 |
82.5% | 100 |
55% | 80 |
? | 50 |
We want to determine the score on the last test for which Mark earns 70 % of the total points on the tests. We can use this information to write the percent equation for the total number of points scored. Total Points Scored= 70 %( Total Point Value) Now, we can consider the given table.
Test Score | Point Value |
---|---|
79 % | 200 |
95.5 % | 100 |
55 % | 80 |
? | 50 |
First, we can use the table to calculate the number of points scored on each test. We can do so by multiplying the test score by the point value for each test. Remember that we can represent the score on the last test with an arbitrary variable a.
Test Score | Point Value | Points Scored |
---|---|---|
79 % | 200 | 79 %* 200 = 158 |
82.5 % | 100 | 82.5 %* 100 = 82.5 |
55 % | 80 | 55 %* 80 = 44 |
a % | 50 | a %* 50 = 0.5a |
Now, we can calculate the sum of all point values and the sum of points scored in each test.
Test Score | Point Value | Points Scored |
---|---|---|
79 % | 200 | 79 %* 200 = 158 |
82.5 % | 100 | 82.5 %* 100 = 82.5 |
55 % | 80 | 55 %* 80 = 44 |
a % | 50 | a %* 50 = 0.5a |
Sum | = 430 | = 284.5+0.5a |
Finally, we can substitute the values in our equation. Total Points Scored= 70 %( Total Point Value) ⇕ 284.5+0.5a= 70 % * 430 Now, we can solve the equation for a.
We found that Mark must get 301 in total from all four tests. Next, we will subtract 284.5 from both sides of the equation.
Finally, we will divide both sides of the equation by 0.5 to get the variable a alone.
Mark needs to score 33 % on the last test to be able to pass the course.