Pearson Geometry Common Core, 2011
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Pearson Geometry Common Core, 2011 View details
2. Perpendicular and Angle Bisectors
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Exercise 32 Page 298

If a line and a segment are perpendicular, they form a right angle. If PM bisects AB, then AM=BM.

Statements
Reasons
1.
PM ⊥ AB, PM bisects AB
1.
Given
2.
m∠ PMA=m∠ PMB=90^(∘)
2.
Definition of Perpendicular Lines
3.
∠ PMA≅∠ PMB
3.
Definition of Angle Congruence
4.
AM=BM
4.
Definition of Bisector
5.
AM≅BM
5.
Definition of Segment Congruence
6.
PM≅PM
6.
Reflexive Property of Congruence
7.
△ PMA≅△ PMB
7.
SAS Congruence Theorem
8.
AP ≅ BP
8.
Definition of Congruent Triangles
9.
AP=BP
9.
Definition of Segment Congruence
Practice makes perfect

To prove the Perpendicular Bisector Theorem, we will write a two-column proof.

Given:& PM ⊥ AB, PM bisects AB Prove:& AP=BP We will begin by stating the given statement. Given PM ⊥ AB, PM bisects AB

Since PM ⊥ AB, we can say that ∠ PMA and ∠ PMB are right angles by definition of perpendicular lines. Definition of Perpendicular Lines m∠ PMA=m∠ PMB=90^(∘) Recall that all right angles are congruent. Definition of Angle Congruence ∠ PMA≅∠ PMB Given that PM bisects AB, the distance from A to M is the same as the distance from M to B. Definition of Bisector AM=BM If the line segments have the same lengths, then they are congruent. Definition of Segment Congruence AM≅BM Considering the Reflexive Property of Congruence, we can write the next step of our proof. Reflexive Property of Congruence PM≅PM So far, we have shown that two sides and the included angle of △ PMA are congruent to two sides and the included angle of △ PMB. Therefore, by the Side-Angle-Side Congruence Theorem, these two triangles are congruent. SAS Congruence Theorem △ PMA≅△ PMB Knowing that the corresponding parts of congruent triangles are congruent, we can say that AP is congruent to BP. Definition of Congruent Triangles AP ≅ BP Finally, to complete our proof, we will use the fact that two congruent segments have the same length. Definition of Segment Congruence AP=BP Combining all of these steps, we can form our two-column proof.

Statements
Reasons
1.
PM ⊥ AB, PM bisects AB
1.
Given
2.
m∠ PMA=m∠ PMB=90^(∘)
2.
Definition of Perpendicular Lines
3.
∠ PMA≅∠ PMB
3.
Definition of Angle Congruence
4.
AM=BM
4.
Definition of Bisector
5.
AM≅BM
5.
Definition of Segment Congruence
6.
PM≅PM
6.
Reflexive Property of Congruence
7.
△ PMA≅△ PMB
7.
SAS Congruence Theorem
8.
AP ≅ BP
8.
Definition of Congruent Triangles
9.
AP=BP
9.
Definition of Segment Congruence