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Complementary angles have a sum of 90^(∘).
See solution.
We are given a paragraph proof with several blanks and asked to fill in those blank spaces. Let's begin by looking at the given information and the desired outcome of the proof. Given:& ∠1 and ∠2 are complementary. & ∠2 and∠3 are complementary. Prove:& ∠1 ≅ ∠3 Now, let's take a look at the statements that need to be completed one at a time.
\begin{gathered} \underline\textbf{Statement}\\ \text{By the definition of complementary angles,}\\ m\angle1+m \angle2= \textbf{a. }\underline{\,90\,} \text{ and } m\angle3 +m\angle2= \textbf{b. }\underline{\,90\,}. \end{gathered}
Our next statement creates an equation using the Transitive Property of Equality and then asks us to subtract m∠2 from either side. m ∠ 1+m ∠2=m ∠ 3 +m ∠ 2 -m ∠ 2 -m ∠ 2 m ∠ 1 = m ∠ 3 Now, we can use this calculation to fill in the appropriate blank. \begin{gathered} \underline\textbf{Statement}\\ \text{By the Subtraction Property of Equality,}\\ \text{you get }m\angle1 = \textbf{ c.}\underline{\,m\angle3\,}. \end{gathered}
Our last statement is asking us to think about the relationship between angles which have the same measure. Angles that have the same measure are considered congruent. This is also the meaning of the symbol ( ≅) used in the conclusion. Let's fill in the last blank! \begin{gathered} \underline\textbf{Statement}\\ \text{Angles with the same measure are }\\ \textbf{d. } \underline{\text{congruent}}, \text{ so }\angle1 \cong \angle3. \end{gathered}
Considering the given information, we can summarize all the steps in a paragraph proof. Given:& ∠1 and ∠2 are complementary. & ∠2 and∠3 are complementary. Prove:& ∠1 ≅ ∠3 Proof: ∠1 and ∠2 are complementary and ∠3 and ∠2 are complementary because it is given. By the definition of complementary angles, m∠1+m∠2= a. 90 and m∠3 +m∠2= b. 90. Then m∠1+m∠2=m∠3 +m∠2 by the Transitive Property of Equality. Subtract m∠2 from each side. By the Subtraction Property of Equality, you get m∠1 = c.m∠3. Angles with the same measure are d. congruent, so ∠1 ≅ ∠3.