Pearson Geometry Common Core, 2011
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Pearson Geometry Common Core, 2011 View details
1. Tangent Lines
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Exercise 42 Page 769

Notice that the given figure is a 45^(∘)-45^(∘)-90^(∘) triangle.

11 sqrt(2)/2

Practice makes perfect

Notice that the given right triangle has a marked angle measuring 45^(∘). Therefore, by the Triangle Angle Sum Theorem, the measure of the third angle must also be 45^(∘).

In a 45^(∘)-45^(∘)-90^(∘) triangle, the legs are congruent and the hypotenuse is sqrt(2) times the length of a leg. With this information, we can find a. 11 & =a sqrt(2) Finally, we can find the simplest expression for a.
11 = a sqrt(2)
11 sqrt(2) = a sqrt(2) * sqrt(2)
11 sqrt(2) = a(sqrt(2))^2
11 sqrt(2) = a(2)
11 sqrt(2)/2 = a
a = 11 sqrt(2)/2