Exercise 35 Page 673

We will start by solving the inequality. Then, we will find the probability that a point chosen at random from $\overline{A K}$ satisfies the inequality.

Solving the Inequality

Let's solve

5 \leq 11 - 6 x .

5 \leq 11 - 6 x

▼

Solve for

x

SubIneq

$LHS - 5 \leq RHS - 5$

0 \leq 6 - 6 x

AddIneq

$LHS + 6 x \leq RHS + 6 x$

6 x \leq 6

DivIneq

$LHS / 6 \leq RHS / 6$

x \leq 1

We found that

x

is less than or equal to

1 .