Let's calculate both solutions by using the positive and negative signs.
x=21±3
x=21+3
x=21−3
x=24
x=2-2
x=2
x=-1
Finally, we will check if either x=2 or x=-1 is an extraneous solution. To do this, we need to substitute 2 and -1 for x in the original equation. Let's start with x=2.
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