Pearson Algebra 2 Common Core, 2011
PA
Pearson Algebra 2 Common Core, 2011 View details
3. Linear Functions and Slope-Intercept Form
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Exercise 62 Page 80

Practice makes perfect
a To determine the slope between a pair of points we use the Slope Formula. In this formula, x_1 and y_1 are coordinates of the first point, while x_2 and y_2 are coordinates of the second point.
m=y_2-y_1/x_2-x_1 This time we have a line that passes through (2,5) and (6,7). We will substitute x_1= 2, y_1= 5, x_2= 6, and y_2= 7 into the formula to find m.
m=y_2-y_1/x_2-x_1
m=7- 5/6- 2
m=2/4
m=1/2
We want to find the equation of the line passing through this pair of points. To do so, we will recall the slope-intercept form of a line. y = mx+ b In this equation, y and x are the coordinates of a point in the line, m is the slope, and b indicates the y-intercept. We will substitute m= 12, x= 2, and y= 5 into this formula to get a partial equation of the line. y = mx+ b ⇓ 5=( 1/2)( 2)+ b Let's solve for b!
5=(1/2)(2)+b
5=2/2+b
5=1+b
4=b
b=4
Now that we know both the slope m and the y-intercept b we can write the complete equation of the line. y= 1/2x+ 4
b We want to find the equation of the line passing through (- 4,16) and (3,- 5). To find it, we will start by finding the slope. Let's recall the Slope Formula.
m=y_2-y_1/x_2-x_1 We will substitute x_1= -4, y_1= 16, x_2= 3, and y_2= -5 into this formula and evaluate it for m.
m=y_2-y_1/x_2-x_1
m=-5- 16/3-( -4)
m=-21/7
m=-3
Next, we will recall the slope-intercept form of the line. y = mx+ b We will substitute m= - 3, x= -4, and y= 16 into this equation to get a partial equation of the line. y = mx+ b ⇓ 16=( -3)( -4)+ b As we can see, we need to find the value of the y-intercept. To find it, we will solve the above equation for b.
16=(-3)(-4)+b
16=12+b
4=b
b=4
Now that we know both the slope m and the y-intercept b, we can write the complete equation of the line in slope-intercept form. y= -3x+ 4
c We want the equation of the line passing through (- 2, 17) and (2,1). We can start by recalling the Slope Formula to find the slope of this line.
m=y_2-y_1/x_2-x_1 We will substitute x_1= - 2, y_1= 17, x_2= 2, and y_2= 1 into this formula and evaluate it for m.
m=y_2-y_1/x_2-x_1
m=1- 17/2-( -2)
m=-16/4
m=-4
Since we want the equation of the line, we can recall the slope-intercept form of a line. y = mx+ b We will substitute m= - 4, x= - 2, and y= 17 into this equation to get a partial equation of the line. y = mx+ b ⇓ 17=( -4)( -2)+ b Next, we will solve this equation to find the value of b. Let's do it!
17=(-4)(-2)+b
17=8+b
9=b
b=9
Now that we know the slope m and the y-intercept b, we can write the complete equation of the line in slope-intercept form. y= -4x+ 9