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Start with the Slope Formula, then use that to create the slope-intercept form for each pair of coordinates.
Start with the Slope Formula, then use that to create the slope-intercept form for each pair of coordinates.
Start with the Slope Formula, then use that to create the slope-intercept form for each pair of coordinates.
y=1/2x+4
y=-3x+4
y=-4+9
To determine the slope between a pair of points we use the Slope Formula. In this formula, x_1 and y_1 are coordinates of the first point, while x_2 and y_2 are coordinates of the second point.
m=y_2-y_1/x_2-x_1
This time we have a line that passes through (2,5) and (6,7). We will substitute x_1= 2, y_1= 5, x_2= 6, and y_2= 7 into the formula to find m.
Substitute ( 2,5) & ( 6,7)
Subtract terms
a/b=.a /2./.b /2.
We want to find the equation of the line passing through this pair of points. To do so, we will recall the slope-intercept form of a line. y = mx+ b In this equation, y and x are the coordinates of a point in the line, m is the slope, and b indicates the y-intercept. We will substitute m= 12, x= 2, and y= 5 into this formula to get a partial equation of the line. y = mx+ b ⇓ 5=( 1/2)( 2)+ b Let's solve for b!
a/c* b = a* b/c
a/a=1
LHS-1=RHS-1
Rearrange equation
Now that we know both the slope m and the y-intercept b we can write the complete equation of the line. y= 1/2x+ 4
We want to find the equation of the line passing through (- 4,16) and (3,- 5). To find it, we will start by finding the slope. Let's recall the Slope Formula.
m=y_2-y_1/x_2-x_1
We will substitute x_1= -4, y_1= 16, x_2= 3, and y_2= -5 into this formula and evaluate it for m.
Substitute ( -4,16) & ( 3,-5)
a-(- b)=a+b
a/b=.a /7./.b /7.
Next, we will recall the slope-intercept form of the line. y = mx+ b We will substitute m= - 3, x= -4, and y= 16 into this equation to get a partial equation of the line. y = mx+ b ⇓ 16=( -3)( -4)+ b As we can see, we need to find the value of the y-intercept. To find it, we will solve the above equation for b.
(- a)(- b)=a* b
LHS-12=RHS-12
Rearrange equation
Now that we know both the slope m and the y-intercept b, we can write the complete equation of the line in slope-intercept form. y= -3x+ 4
We want the equation of the line passing through (- 2, 17) and (2,1). We can start by recalling the Slope Formula to find the slope of this line.
m=y_2-y_1/x_2-x_1
We will substitute x_1= - 2, y_1= 17, x_2= 2, and y_2= 1 into this formula and evaluate it for m.
Substitute ( -2,17) & ( 2,1)
a-(- b)=a+b
a/b=.a /4./.b /4.
Since we want the equation of the line, we can recall the slope-intercept form of a line. y = mx+ b We will substitute m= - 4, x= - 2, and y= 17 into this equation to get a partial equation of the line. y = mx+ b ⇓ 17=( -4)( -2)+ b Next, we will solve this equation to find the value of b. Let's do it!
(- a)(- b)=a* b
LHS-8=RHS-8
Rearrange equation
Now that we know the slope m and the y-intercept b, we can write the complete equation of the line in slope-intercept form. y= -4x+ 9