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Recall the general form of an absolute value function.
(1/b,c), see solution.
Let's start by recalling the general form of an absolute value function.
f(x)= a|x- h|+ k
In this form, the vertex of the graph of the function is the point ( h, k). Now, consider the given function.
We are now able to identify the vertex of the graph of this function. f(x)= a|b||x- 1/b|+ c The vertex is the point ( 1b,c). This means that the graph of f(x) changes direction at the point ( 1b,c).
Note that in both cases, we can find the x-value of the vertex by setting the expression inside the absolute value, bx-1, equal to 0.
Now that we know the x-value of the vertex, we can find its y-value by substituting x= 1b into our function.
x= 1/b
b * a/b= a
1-1=0
|0|=0
Zero Property of Multiplication
Identity Property of Addition
We found that f( 1b) is equal to c. This is the y-value of the vertex. Therefore, the vertex of the graph of the given function is ( 1b,c).