We are given that the quadratic function y= ax^2+ bx+ c passes through the following three points.
(0,0), (1,2), (3, -6)
We will first find the coefficients and the constant of our equation. To do so, since those three points satisfy our equation we will substitute them into the equation one at a time. Let's begin with (0,0).
Since we got two equations with the same variables, we will now solve the following system.
a+ b =2
3a + b = - 2
To do so we can use the Elimination Method by subtracting the first equation from the second one.
Having all the coefficients, we can complete our equation. Let's see it!
y = -2x^2 + 4x + 0
Now we will find the axis of symmetry of the given parabola. To do so, remember the formula for the axis of symmetry.
x= - b/2a
Since we have found that a= -2 and b= 4, we can substitute those values and solve for x.
