Pearson Algebra 2 Common Core, 2011
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Pearson Algebra 2 Common Core, 2011 View details
End-of-Course Assessment

Exercise 26 Page 966

Practice makes perfect
a We will find the inverse of the following function.
To do so we first need to replace with From there, we switch and and solve for
The resulting equation will be the inverse of the given function.
Solve for
Finally, to indicate that this is the inverse function of we will replace with
b Let's begin with finding To do so we will substitute into our function, Let's remember that we found in Part A.
Therefore, we will substitute into the function
Simplify right-hand side
Great! Next, we will find This time we will substitute into our inverse function,
Let's plug into the inverse function
Simplify right-hand side
We can conclude that the outputs for both of the composite functions are
Moreover, since the inputs and also the outputs are the same for and they are called identity functions.
c We will examine the domain and range of the functions and Let's begin with
Note that is a rational function which is only undefined where the denominator is zero.
Since its denominator is at its domain is all real numbers except Now, let's recall that the range is the set of all outputs of a function. Notice that the division of a number by another number never gives Therefore, the range of the function is the set of all real numbers except
Now, let's examine the function
Since is also a rational function, it is undefined where Therefore, its domain is all real numbers except For the range, since never equals we cannot get as a result. Therefore, the range of the inverse function is the set of real numbers except
Notice that the range of becomes the domain of and the domain of becomes the range of