Pearson Algebra 2 Common Core, 2011
PA
Pearson Algebra 2 Common Core, 2011 View details
6. Angle Identities
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Exercise 15 Page 949

Use the definitions of the trigonometric ratios for a right triangle.

tan A

Practice makes perfect

We are given a trigonometric expression. cot (90^(∘) - A) We will consider that A is an acute angle of a right triangle. The acute angles of a right triangle are complementary, which means that their sum is 90 ^(∘). A+ B = 90^(∘)We can rewrite this sum as a difference that will allow us to rewrite the given expression. 90^(∘)- A= B ⇓ cot (90^(∘) - A) = cot B We want to derive a cofunction identity for the given expression. To do so, we will start by drawing a right triangle ABC.

Now, let's recall the trigonometric ratios for both tangent and its reciprocal ratio, cotangent. tan θ=Opposite/Adjacent cot θ=Adjacent/Opposite Since we have cot B, we need the length of the opposite and adjacent side to ∠ B. From the diagram, we can see that b is the opposite side to B and a is their adjacent side. We will substitute these values into the expression for cotangent ratio. cot B = Adjacent/Opposite=a/b We can rewrite this equation using tangent by noting that b is the length of the adjacent side and a is the length of the opposite side angle to A. Then, we will have the quotient between the opposite and the adjacent side to ∠ A.

Finally, we can write the cofunction identity for the given expression. cot (90^(∘) - A) = tan A