Pearson Algebra 2 Common Core, 2011
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Pearson Algebra 2 Common Core, 2011 View details
6. Angle Identities
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Exercise 13 Page 949

Use the definitions of the trigonometric ratios for a right triangle.

cot A

Practice makes perfect
We are given a trigonometric expression. tan (90^(∘) - A) Consider that A is an acute angle of a right triangle. The acute angles of a right triangle are complementary, which means that their sum is 90 ^(∘). A+ B = 90^(∘)

We can rewrite this sum as a difference that will allow us to rewrite the given expression. 90^(∘)- A= B ⇓ tan (90^(∘) - A)=tan B We want to derive a cofunction identity for the given expression. To do so, we will start by drawing a right triangle ABC.

Now, let's recall the trigonometric ratios for both tangent and its reciprocal ratio, cotangent. cc tan θ=Opposite/Adjacent & cot θ=Adjacent/Opposite Since we have tan B, we need the opposite and adjacent sides to ∠ B. From the diagram, we can see that b is the opposite side to B and a is its adjacent side. We will substitute these values into the expression for tangent ratio. tan B = Opposite/Adjacent=b/a We can rewrite this equation using cotangent by noting that b is the length of the adjacent side and a is the length of the opposite side angle to A. Then, we will have the quotient between the adjacent and the opposite side to ∠ A.
Finally, we can write the cofunction identity for the given expression. tan (90^(∘) - A) = cot A