body{margin:0;} noscript{z-index: 10000; position: fixed; display: block; height: 100%; width: 100%; background: #fff;} noscript .fa{font-size: 40px; display:block; color: #daa520;} noscript div{margin-top: 6%; padding-left: 20px; padding-right: 20px; text-align: center;} ! You must have JavaScript enabled to use this site.

Pearson Algebra 2 Common Core, 2011

PA

Pearson Algebra 2 Common Core, 2011 View details

Cumulative Standards Review

Exercise 9 Page 899

Use the definition of a logarithm.

B

Practice makes perfect

To write the given equation in logarithmic form, we should recall the definition of a logarithm.

x = b^{y} \Leftrightarrow lo g_{b} x = y

The above relationship tells us that the logarithm

y

is the exponent to which

b

must be raised to get

x .

Let's now apply the definition to the given equation.

2^{9} = 512 \Leftrightarrow lo g_{2} 512 = 9

This corresponds to option B.

Subchapter links

Exercises p.898-900

Vocabulary Review