Pearson Algebra 1 Common Core, 2011
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Pearson Algebra 1 Common Core, 2011 View details
4. Factoring to Solve Quadratic Equations
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Exercise 57 Page 572

To factor a trinomial with a leading coefficient of 1, think of the process as multiplying two binomials in reverse.

(y-5)^2

Practice makes perfect
To factor a trinomial with a leading coefficient of 1, think of the process as multiplying two binomials in reverse. Let's start by taking a look at the constant term. y^2-10y+25 In this case, we have 25. This is a positive number, so for the product of the constant terms in the factors to be positive, these constants must have the same sign (both positive or both negative.)
Factor Constants Product of Constants
1 and 25 25
-1 and -25 25
5 and 5 25
-5 and -5 25

Next, let's consider the coefficient of the linear term. y^2-10y+25 For this term, we need the sum of the factors that produced the constant term to equal the coefficient of the linear term, -10.

Factors Sum of Factors
1 and 25 26
-1 and -25 -26
5 and 5 10
-5 and -5 -10

We found the factors whose product is 25 and whose sum is -10. y^2-10y+25 ⇔ (y-5)(y-5) Both factors are the same, so we can write the expression as (y-5)^2.