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To factor a trinomial with a leading coefficient of 1, think of the process as multiplying two binomials in reverse.
(g-7)^2
To factor a trinomial with a leading coefficient of 1, think of the process as multiplying two binomials in reverse. Let's start by taking a look at the constant term.
g^2-14g+49
In this case, we have 49. This is a positive number, so for the product of the constant terms in the factors to be positive, these constants must have the same sign (both positive or both negative.)
| Factor Constants | Product of Constants |
|---|---|
| 1 and 49 | 49 |
| -1 and -49 | 49 |
| 7 and 7 | 49 |
| -7 and -7 | 49 |
Next, let's consider the coefficient of the linear term. g^2-14g+49 For this term, we need the sum of the factors that produced the constant term to equal the coefficient of the linear term, -14.
| Factors | Sum of Factors |
|---|---|
| 1 and 49 | 50 |
| -1 and -49 | -50 |
| 7 and 7 | 14 |
| -7 and -7 | -14 |
We found the factors whose product is 49 and whose sum is -14. g^2-14g+49 ⇔ (g-7)(g-7) Both factors are the same, so we can write the expression as (g-7)^2.