Pearson Algebra 1 Common Core, 2011
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Pearson Algebra 1 Common Core, 2011 View details
5. Linear Inequalities
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Exercise 40 Page 399

Begin by finding the discounted cost of both items.

Inequality: 3.10x+2.40y ≤ 20
Graph:

Practice makes perfect
To begin we can determine the discounted cost of both items. It is given that the original cost per gallon of milk is $3.60 and that it is discounted by $0.50. Subtracting gives us the discounted price of milk. 3.60-0.50=$3.10 It's also given that the original cost of meat is $3.00 per pound and that it is discounted 20 %. To determine the discounted price of meat, we will find 20 % of 3.00 and subtract it from 3.00.

3.00- 0.20 * 3.00 = $2.40

Writing an Inequality

Let x represent the number of gallons of milk we buy, while y represents the number of pounds of meat we buy. Therefore, we will pay $3.10* x for the milk and $2.4* y for the meat. Since it is given that we want to spend no more than 20 dollars, we can write the inequality. 3.10x+2.40y ≤ 20

Graphing the Inequality

To graph the inequality, we first have to express it in slope-intercept form. To do so, we will isolate y.
3.10x+2.40y ≤ 20
â–Ľ
Solve for y
2.40y ≤ - 3.10x+20
y ≤ - 3.10x+20/2.40
y ≤ - 3.10x/2.40+20/2.40
y ≤ - 1.3x+ 8.3
Now that the inequality is written as y ≤ - 1.3x+ 8.3, we can see that the slope of the boundary line is 1.3 and the y-intercept is 8.3. We will use these to graph the boundary line. Since the symbol is ≤ the line will be solid and we will shade the area below the graph.

The graph only makes sense in the first quadrant, since it's impossible to buy a negative amount of meat or milk.