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PA

Pearson Algebra 1 Common Core, 2011 View details

Cumulative Standards Review

Finish the assignment

Exercise 3 Page 413

To isolate x, first isolate x+1.

C

Practice makes perfect

To solve this type of equation, we will use the Properties of Equality to isolate the variable.

Solving the Equation

For this exercise, we will start by using the Division Property of Equality to isolate the variable term (x+1).

12(x+1)=36

DivEqn

.LHS /12.=.RHS /12.

x+1=3

Next, we need to isolate x on the left-hand side. Using the Subtraction Property of Equality, we will subtract 1 from both sides of the equation to eliminate the 1 from left-hand side of the equation.

x+1=3

SubEqn

LHS-1=RHS-1

x=2

Therefore, x=2 is the solution to the equation. This answer corresponds to option C.