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Pearson Algebra 1 Common Core, 2011

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Pearson Algebra 1 Common Core, 2011 View details

Cumulative Standards Review

Exercise 17 Page 414

To isolate x, first isolate -3x+6.

x=-1

Practice makes perfect

To solve this type of equation, we will use the Properties of Equality to isolate the variable.

Solving the Equation

For this exercise, we will start by using the Subtraction Property of Equality to isolate the variable term 4(-3x+6).

4(-3x+6)-1=-13

LHS+1=RHS+1

4(-3x+6)=-12

Next, we need to isolate x on the left-hand side by using the Properties of Equality.

4(-3x+6)=-12

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Solve for x

.LHS /4.=.RHS /4.

4(-3x+6)/4=- 12/4

MoveNegNumToFrac

Put minus sign in front of fraction

4(-3x+6)/4=- 12/4

Calculate quotient

-3x+6=-3

LHS+6=RHS+6

-3x=3

.LHS /(-3).=.RHS /(-3).

x=-1

Therefore, x=- 1 is the solution to the equation.

Subchapter links

Exercises p.412-414