Pearson Algebra 1 Common Core, 2011
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Pearson Algebra 1 Common Core, 2011 View details
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Exercise 8 Page 409

Is the equation in slope-intercept form? What information can the slope-intercept form of an equation give you?

(-14/3,-35/3)

Practice makes perfect

By graphing the given equations, we can solve the system. If a solution exists, it will be the point at which the lines intersect. To do this, we will need the equations to be in slope-intercept form to help us identify the slope m and y-intercept b.

Write in Slope-Intercept Form

Let's rewrite each of the equations in the system in slope-intercept form, highlighting the m and b values.

Given Equation Slope-Intercept Form Slope m y-intercept b
y=- 2x-21 y=- 2x+( - 21) - 2 (0, - 21)
y= x-7 y=1x+( - 7) 1 (0, -7)

Graphing the System

To graph these equations, we will start by plotting their y-intercepts. Then we will use the slope to determine another point that satisfies each equation, and connect the points with a line.

Notice that the slope indicated for the second equation is shown as 22. This is okay because slope is the rise divided by the run. m=rise/run ⇒ m=1/1=2/2 We can see that the lines intersect at exactly one point.

However, we cannot identify the intersection point precisely. We can estimate that the intersection point is approximately (-4.6,-11.8). Now, let's check whether the point satisfies the equations.
y=-2x-21 & (I) y=x-7 & (II)

(I), (II): x= -4.6, y= -11.8

-11.8? =-2( -4.6)-21 -11.8? = -4.6-7
-11.8? =9.2-21 -11.8? =-4.6-7

(I), (II): Subtract term

-11.8=-11.8 -11.8≠ -11.6
The intersection point satisfies the first equation but it does not satisfy the second equation. The conclusion is that we cannot solve this system by graphing. Therefore, we will use the Substitution Method.

Substitution Method

Let's use the Substitution Method to solve the system of equations. Since the y-variables are already isolated, we will start with substituting x-7 for y into the first equation.
y=-2x-21 & (I) y=x-7 & (II)
x-7=-2x-21 y=x-7
3x-7=-21 y=x-7
3x=-14 y=x-7
x=- 143 y=x-7
The x-coordinate of the intersection point is - 143. Next, we will find the y-coordinate.
x=- 143 y=x-7
x=- 143 y= - 143-7
x=- 143 y=- 143- 213
x=- 143 y=- 353
As a result, the intersection point is (- 143,- 353).

Checking Our Solution

Now, we will check the point to make sure it works.
y=-2x-21 & (I) y=x-7 & (II)

(I), (II): x= -14/3, y= -35/3

- 353? =-2( - 143)-21 - 353? = - 143-7
- 353? = 283-21 - 353? =- 143-7

(I), (II): a = 3* a/3

- 353? = 283- 633 - 353? =- 143- 213

(I), (II): Subtract fractions

- 353=- 353 - 353=- 353
Since we have reached an identity in both equations, (- 143,- 353). is the solution of the system of equations.