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Pearson Algebra 1 Common Core, 2011

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Pearson Algebra 1 Common Core, 2011 View details

Mid-Chapter Quiz

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Exercise 8 Page 115

Gather all of the variable terms on one side of the equation and all of the constant terms on the other side.

Identity

Practice makes perfect

To solve an equation, we should first gather all of the variable terms on one side of the equation and all of the constant terms on the other side using the Properties of Equality. In this case, we need to start by using the Distributive Property to simplify the left- and right-hand sides of the equation.

1/7(14-7p)-2=-2(1/2p+3)+6

Distribute 1/7

2-p-2=-2(1/2p+3)+6

Distribute -2

2-p-2=- p-6+6

Add and subtract terms

- p = - p

.LHS /(-1).=.RHS /(-1).

p=p

Simplifying the equation resulted in an identity. Thus, the equation has infinitely many solutions.