When adding or subtracting fractions, they should have the same denominator. In this exercise, we have two fractions with different denominators.

\frac{1 6}{2 5} + \frac{3}{1 0}

To find the smallest common denominator we should rewrite the denominators of both fractions using only prime numbers.

25 = 5 \cdot 5 10 = 2 \cdot 5

Now, in order to get a common denominator we need to multiply each fraction by factors that appear only in the denominator of the other fraction. Therefore, we multiply

\frac{1 6}{2 5}

by

2

and

\frac{3}{1 0}

by

5 .

\frac{1 6}{2 5} + \frac{3}{1 0}

ExpandFrac

$\frac{a}{b} = \frac{a \cdot 2}{b \cdot 2}$

\frac{1 6 \cdot 2}{2 5 \cdot 2} + \frac{3}{1 0}

ExpandFrac

$\frac{a}{b} = \frac{a \cdot 5}{b \cdot 5}$

\frac{1 6 \cdot 2}{2 5 \cdot 2} + \frac{3 \cdot 5}{1 0 \cdot 5}

Multiply

\frac{3 2}{5 0} + \frac{1 5}{5 0}

Now that we have a common denominator, we can proceed to simplifying the expression.

\frac{3 2}{5 0} + \frac{1 5}{5 0}

AddFrac

Add fractions

\frac{3 2 + 1 5}{5 0}

AddTerms

Add terms

\frac{4 7}{5 0}

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