McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
Mid-Chapter Quiz
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Exercise 12 Page 434

Use the Midpoint Formula to find the midpoint D of JK. Then, use the Centroid Theorem.

(- 3,2)

Let's start by plotting the given points on a coordinate plane and drawing â–ł JKL.

To find the location of the centroid, we need to recall two definitions.

  1. The centroid describes the point of concurrency of the triangle's medians.
  2. A medians of a triangle is a segment with one endpoint being a vertex and the other endpoint being the midpoint of the opposite side.

Let's draw the medians of our triangle.

To find the coordinates of P, we will first find the coordinates of the midpoint D of JK. Then, we will use the Centroid Theorem.

Midpoint of JK

To find the coordinates of D, we will substitute the coordinates of J and K into the Midpoint Formula.
(x_1+x_2/2,y_1+y_2/2)
(- 5+( - 5)/2,5+( - 1)/2)
(- 5-5/2,5-1/2)
(- 10/2,4/2)
(- 5,2)
The coordinates of D are (- 5,2). We can plot this point on our diagram and focus the median of JK.

Using the Centroid Theorem

By the Centroid Theorem, we know that the centroid is two thirds of the distance from each vertex to the midpoint of the opposite side. Thus, we have PL= 23DL.

We see that DL is a horizontal line. The distance from D( - 5, 2) to L( 1, 2) is 6 units. 1 - ( - 5) = 6 Now that we know DL, we can find PL.
PL = 2/3 DL
PL=2/3( 6)
PL=12/3
PL=4
This means that the centroid is 4 units to the left of L. Therefore, subtracting 4 from the x-coordinate of L( 1, 2) will give us the coordinates of the centroid. ( 1- 4, 2) ⇔ (- 3,2)