McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
Mid-Chapter Quiz
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Exercise 16 Page 434

a Let's put the information we are given on the diagram.

Source: OpenStreetMap

Notice that all angles of the triangle △ ABC are expressed in terms of m∠ B. Let's use the Triangle Angle-Sum Theorem to set up and solve an equation for m∠ B.
m∠ A+m∠ B+m∠ C=180
2+m∠ B+m∠ B+ 2(m∠ B)-14=180
Solve for m∠ B
4(m∠ B)-12=180
4(m∠ B)=192
m∠ B=48
We can use this value and the expressions m∠ A=2+m∠ B and m∠ C=2(m∠ B)-14 to find the measure of the other two angles.
Angle Expression Measure
∠ A 2+48 m∠ A=50
∠ B 48 m∠ B=48
∠ C 2(48)-14 m∠ C=82
b Let's replace the expressions with the measure of the angles we got in part A. Let's also replace the label of the points with the name of the cities.

We can use the Angle-Side Relationships in Triangles to compare the lengths of the three legs of Kailey's trip.

  • The shortest leg is opposite to the angle with smallest measure, so it is between Kahuku and Waimanalo.
  • The next leg is the one opposite to Waimanalo, so it is between Nanakuli and Kahuku.
  • The longest leg is opposite to the angle with greatest measure, so it is between Waimanalo and Kahuku.
c To be able to use algebra to answer this part, let's introduce variables and write equations to express the information given in the question in terms of these variables.
Information Variable/Expression
Length of the shortest leg. s
Length of the middle leg. m
Length of the longest leg. l
The middle leg is 11 miles greater than one-half the length of the shortest leg. m=1/2s+11
The longest leg is 12 miles greater than three-fourths of the shortest leg. l=3/4s+12
The length of the entire trip is 68 miles. s+m+l=68
Notice that we have an expression for both l and m in terms of s. We can use these expressions to replace l and m in the last equation to set up and solve an equation for s.
s+m+l=68
s+ 1/2s+11+ 3/4s+12=68
Solve for s
4s+2s+44+3s+48=272
9s+92=272
9s=180
s=20
We can use this value and the expressions m=1/2s+11 and l=3/4s+12 to find the length of the other two legs.
Leg Expression Length
s 20 20 miles
m 1/2(20)+11 21 miles
l 3/4(20)+12 27 miles

Combining this result with the order we found in part B, we get the following distances.

Leg Length
From Kahuku to Waimanolo 20 miles
From Nanakuli to Kahuku 21 miles
From Waimanolo to Nanakuli 27 miles