Mid-Chapter Quiz
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Source: OpenStreetMap
Notice that all angles of the triangle △ ABC are expressed in terms of m∠ B. Let's use the Triangle Angle-Sum Theorem to set up and solve an equation for m∠ B.m∠ A= 2+m∠ B, m∠ C= 2(m∠ B)-14
Add and subtract terms
LHS+12=RHS+12
.LHS /4.=.RHS /4.
Angle | Expression | Measure |
---|---|---|
∠ A | 2+48 | m∠ A=50 |
∠ B | 48 | m∠ B=48 |
∠ C | 2(48)-14 | m∠ C=82 |
We can use the Angle-Side Relationships in Triangles to compare the lengths of the three legs of Kailey's trip.
Information | Variable/Expression |
---|---|
Length of the shortest leg. | s |
Length of the middle leg. | m |
Length of the longest leg. | l |
The middle leg is 11 miles greater than one-half the length of the shortest leg. | m=1/2s+11 |
The longest leg is 12 miles greater than three-fourths of the shortest leg. | l=3/4s+12 |
The length of the entire trip is 68 miles. | s+m+l=68 |
Leg | Expression | Length |
---|---|---|
s | 20 | 20 miles |
m | 1/2(20)+11 | 21 miles |
l | 3/4(20)+12 | 27 miles |
Combining this result with the order we found in part B, we get the following distances.
Leg | Length |
---|---|
From Kahuku to Waimanolo | 20 miles |
From Nanakuli to Kahuku | 21 miles |
From Waimanolo to Nanakuli | 27 miles |