McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
5. Radical Equations
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Exercise 39 Page 263

Substitute w=3 into each fraction.

C

Practice makes perfect
We are given four options, each including a fraction with the variable w. Among these options we will find the one that is undefined when w=3. Recall that if the denominator of a fraction is zero, the expression is undefined. Let's now substitute w= 3 into each fraction and solve.
Option Fraction Substitution Result
A w-3/w+1 3-3/3+1=0/4 0
B w^2-3w/3w 3^2-3( 3)/3( 3)=0/9 0
C w+1/w^2-3w 3+1/3^2-3( 3)=4/0 Undefined
D 3w/3w^2 3( 3)/3( 3)^2=9/27 1/3

As we can see from the table, the denominator of the fraction in option C becomes 0 when w is equal to 3. This means that this fraction is undefined when w=3. To see a step-by-step explanation for these calculations, please see the bottom of this solution.

Showing Our Work

Substitution
Let's explain the calculations in the substitutions step-by-step. We will start with the option A and substitute w=3 into the fraction w-3w+1.
w-3/w+1
3-3/3+1
0/4

0/a=0

0
As we can see, the expression is equal to 0 when w=3. Now, let's substitute w=3 into the fraction in option B.
w^2-3w/3w
3^2-3( 3)/3( 3)
9-3(3)/3(3)
9-9/9
0/9

0/a=0

0
We can see that the expression becomes 0 when w=3. We will now substitute w=3 into the fraction in option C.
w+1/w^2-3w
3+1/3^2-3( 3)
3+1/9-3(3)
3+1/9-9
4/0
Notice that the denominator of the fraction in option C is 0. It means that it is undefined when w=3. Finally, let's substitute w=3 into the fraction in option D.
3w/3w^2
3( 3)/3( 3)^2
3(3)/3(9)
9/27
1/3
As we can see, the fraction in option D is 13 when w=3.