McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
5. Radical Equations
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Exercise 30 Page 262

Practice makes perfect
a The radius r of a cylindrical container of chocolate drink mix is expressed by a formula.
r=sqrt(V/Ď€ h) In this formula, V is the volume of the container and h is the height. We are given a container that has the volume of 162 cubic inches. In the case that the radius of the container is 2.5 inches, and we will find its height. To do so let's substitute V= 162 and r= 2.5 into the formula and solve it for h.
r=sqrt(V/Ď€ h)
2.5=sqrt(162/Ď€ h)
â–Ľ
Solve for h
(2.5)^2=(sqrt(162/Ď€ h))^2
6.25=(sqrt(162/Ď€ h))^2
6.25=162/Ď€ h
6.25 h=162/Ď€
h=162/6.25Ď€
h=8.250592...
h=8.25
The height of the container, to the nearest hundredth, is 8.25 inches.
b We will now find the radius of a container that has the volume of 162 cubic inches and the height of 10 inches. To do so, let's substitute V= 162 and h= 10 into the formula and solve it for r.
r=sqrt(V/Ď€ h)
r=sqrt(162/Ď€ ( 10))
r=sqrt(16.2/Ď€)
r=2.270819...
r=2.27
The radius of the container, to the nearest hundredth, is 2.27 inches.