McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
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Exercise 10 Page 225

To algebraically determine the inverse of the given relation, we need to exchange x and y and solve for y.

Inverse: f^(- 1)(x)=2x+1
Graph:

Practice makes perfect
Before we can find the inverse of the given function, we need to simplify f(x) by rewriting it as a sum of quotients. f(x)=x-1/2 ⇔ f(x)=x/2-1/2 ⇔ f(x)=1/2x-1/2 Then, we need to replace f(x) with y. f(x)=1/2x-1/2 ⇔ y=1/2x-1/2To algebraically determine the inverse of the given relation, we exchange x and y and solve for y. ccc Given Equation & & Inverse Equation [0.8em] y=1/2 x-1/2 & & x=1/2 y-1/2 The result of isolating y in the new equation will be the inverse of the given function.
x=1/2y-1/2
Solve for y
x+1/2=1/2y
2x+1=y
y=2x+1
Now we have the inverse of the given function. Lastly, we need to replace y with f^(- 1)(x). y=2x+1 ⇔ f^(- 1)(x)=2x+1

Graphing the Function

Because the given function is in slope-intercept form, we can graph it using its slope and y-intercept. It has a slope of 12 and a y-intercept at (0,- 12).

Graphing the Inverse of the Function

Because the inverse function is in slope-intercept form, we can graph it using its slope and y-intercept. It has a slope of 2 and a y-intercept at (0,1).

Let's add it to the graph of the given function so that we can more easily see how it is a reflection across the y=x.