McGraw Hill Integrated II, 2012
MH
McGraw Hill Integrated II, 2012 View details
Standardized Test Practice

Exercise 1 Page 878

The volume of a pyramid is one third of the product of its base area B and height h.

B

Practice makes perfect
Let's begin with recalling that the volume of a pyramid is one third of the product of its base area B and height h. V=Bh/3We are told that the base of the Great Pyramid was a square with 230-meter sides. The area of a square can be found by squaring its side length. Hence, raising 230 to the power of 2, we can calculate the area of the pyramid's base. B=230^2=52 900m^2 It is also given that the original height of the Great Pyramid was about 148 meters. Let's substitute B with 52 900 and h with 148 into the formula and calculate the volume V of the pyramid.
V=Bh/3
V=( 52 900)( 148)/3
V=2 609 733.33333...
V≈ 2 609 733
We conclude that the original volume of the Great Pyramid was approximately 2 609 733 cubic meters. Therefore, the answer is B.