McGraw Hill Glencoe Algebra 1, 2017
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McGraw Hill Glencoe Algebra 1, 2017 View details
1. Writing Equations in Slope-Intercept Form
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Exercise 1 Page 228

Equations in slope-intercept form follow a certain format. y= mx+ b In this form, the coefficient m is the slope and the constant b is the y-intercept. We are told that the line has a slope of 3, which means that we can substitute m= 3. y= 3x+ b To write a complete equation for this line, we also need to determine the y-intercept b. We can do that by substituting the given point ( 3, -3) into the equation and solving for b.
y=3x+b
- 3=3( 3)+b
â–Ľ
Solve for b
- 3=9+b
- 12=b
b= - 12
Now that we have both the slope and the y-intercept, we can write the final equation. y= 3x+( - 12) ⇔ y= 3x - 12 Let's take a look at the graph of this line by showing it on a coordinate plane.

Alternative Solution

Using Point-Slope Form
There is another form of linear equations called point-slope form. y-y_1=m(x-x_1) In this form, m is still the slope of the line and (x_1,y_1) is a point that lies on the line. With the given information, it is a much quicker process to write the equation of the line using point-slope form. Let's try!
y-y_1=m(x-x_1)
y-( -3)= 3(x- 3)
y+3=3(x-3)
y+3=3x-9
y=3x-12
We got the same equation as before but through a quicker process.