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McGraw Hill Glencoe Algebra 1, 2012

MH

McGraw Hill Glencoe Algebra 1, 2012 View details

1. Solving Inequalities by Addition and Subtraction

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Exercise 81 Page 290

Use the Division Property of Equality to eliminate the multiplication.

$x = - \frac{1}{9}$

Practice makes perfect

To solve the equation, we have to isolate

x

on one side. Using the Division Property of Equality, we will divide both sides of the equation by

- 6 .

This will eliminate the factor

- 6

and isolate

x .

- 6 x = \frac{2}{3}

$LHS / (- 6) = RHS / (- 6)$

x = \frac{2}{3} / (- 6)

▼

Simplify right-hand side

$\frac{a}{b} / c = \frac{a}{b \cdot c}$

x = \frac{2}{3 ( - 6 )}

$\frac{a}{b} = \frac{a / 2}{b / 2}$

x = \frac{1}{3 ( - 3 )}

$a (- b) = - a \cdot b$

x = \frac{1}{- 9}

MoveNegDenomToFrac

Put minus sign in front of fraction

x = - \frac{1}{9}

The solution to the equation is

x = - \frac{1}{9} .

Subchapter links

Check Your Understanding p.288

H.O.T. Problems p.289

Standardized Test Practice p.290

Spiral Review p.290

Skills Review p.290