McGraw Hill Glencoe Algebra 1, 2012
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McGraw Hill Glencoe Algebra 1, 2012 View details
6. Graphing Inequalities in Two Variables
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Exercise 56 Page 322

Try to rewrite this inequality as a compound inequality.

{ t | 1 ≤ t ≤ 11 }

Practice makes perfect
We are asked to find the solution set for all possible values of t in the given inequality. |t-6| ≤ 5 To do this, we will create a compound inequality by removing the absolute value. In this case, the solution set is any number less than 5 away from the midpoint in the positive direction and any number less than 5 away from the midpoint in the negative direction. Absolute Value Inequality:& |t-6| ≤ 5 Compound Inequality:& -5 ≤ t-6 ≤ 5

This compound inequality means that the distance between t and 6 is greater than or equal to - 5 and less than or equal to 5. t-6 ≤ 5 and t-6 ≥ -5 Let's isolate t in both of these cases before determining the solution set.

Case 1

t-6≤5
t≤11
This inequality tells us that all values less than or equal to 11 will satisfy the inequality.

Case 2

t-6≥-5
t≥1
This inequality tells us that all values greater than or equal to 1 will satisfy the inequality.

Solution Set

The solution to this type of compound inequality is the overlap of the solution sets. Let's recombine our cases back into one compound inequality. First Solution Set:& t ≤ 11 Second Solution Set:& 1 ≤ t Intersecting Solution Set:& 1 ≤ t ≤ 11