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Based on the diagram, the following statement holds true.
If ℓ1∥ℓ2 and t⊥ℓ1, then t⊥ℓ2.
It is given that ℓ1 and ℓ2 are parallel lines and the transversal t is perpendicular to the line ℓ1. This means that the lines ℓ1 and t intersect at a right angle.
Angles ∠1 and ∠2 are corresponding angles. By the Corresponding Angles Theorem, ∠1 and ∠2 are congruent. This means that ∠2 is also a right angle.
Therefore, t is perpendicular to ℓ2. This proves the theorem.
If ℓ1∥ℓ2 and t⊥ℓ1, then t⊥ℓ2.