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P(a+bi)=0⇒P(a−bi)=0
P(a+bi)=k=0∑nck(a+bi)k | The conjugate of the polynomial evaluated at a+bi |
P(a+bi)=k=0∑nck(a+bi)k | The conjugate of a sum is the sum of the conjugates. |
P(a+bi)=k=0∑nck (a+bi)k | The conjugate of a product is the product of the conjugates. |
P(a+bi)=k=0∑nck(a+bi)k | The conjugate of a power is the power of the conjugate. |
P(a+bi)=k=0∑nck(a+bi)k | The conjugate of a real number is itself. |
P(a+bi)=k=0∑nck(a−bi)k | The conjugate of a+bi is a−bi. |
P(a+bi)=P(a−bi) | The polynomial evaluated at a−bi |