Houghton Mifflin Harcourt Algebra 1, 2015
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Houghton Mifflin Harcourt Algebra 1, 2015 View details
5. Creating and Solving Compound Inequalities
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Exercise 12 Page 73

Find the upper and lower limits to write two individual inequalities.

- 8 < x ≤ -1

Practice makes perfect

We are asked to find the corresponding compound inequality to the shown graph.

The graph starts with an open circle at -8. This means that -8 is not part of the solution set. However, it is from that point where the shading to the right starts. This means that numbers greater than -8 are part of the solution. Thus, -8 is the lower limit for our inequality.

x > -8 Then, the shading continues until it reaches the value -1, where we have a closed circle. This means that -1 is part of the solution set. Thus, -1 is the upper limit for the inequality. x ≤ -1 Therefore, we now that x>-8 AND x≤ - 1. Hence, x is greater than -8 and at the same time is less than or equal to -1. - 8 < x ≤ -1