Houghton Mifflin Harcourt Algebra 1, 2015
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Houghton Mifflin Harcourt Algebra 1, 2015 View details
5. Creating and Solving Compound Inequalities
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Exercise 4 Page 69

Split the compound inequality into two separate inequalities.

Solution Set: -4 Graph:

Practice makes perfect
First, let's split the compound inequality into separate inequalities. Compound Inequality: -10< 3x&+ 2 ≤ 8 First Inequality: -10< 3x&+2 Second Inequality: 3x &+2 ≤ 8 Notice that compound inequalities written in this way are equivalent to compound inequalities that involve the word "and." -10< 3x+2 and 3x+2 ≤ 8

Let's solve the inequalities separately.

First inequality

Inequalities can be solved in the same way as equations, by performing inverse operations on both sides until the variable is isolated. The only difference is that when you divide or multiply by a negative number, you must flip the inequality sign.
-10< 3x+2
-12<3x
-4
This inequality tells us that - 4 is less than all values that satisfy the inequality.

Note that the point on - 4 is open because it is not included in the solution set.

Second inequality

Once more, we will solve the inequality by isolating the variable.
3x+2≤8
3x≤6
x≤2
This inequality tells us that all values less than or equal to 2 will satisfy the inequality.

Note that the point on 2 is closed because it is included in the solution set.

Compound inequality

The solution to the compound inequality is the intersection of the solution sets. First Solution Set: - 4< x& Second Solution Set: x&≤ 2 Intersecting Solution Set: - 4< x& ≤ 2 Finally, we will graph the solution set to the compound inequality on a number line.