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Recall the formula for speed.
Train A
We are told that two trains, A and B, are traveling at a constant rate. We are asked to determine which train is traveling at a faster rate. First, let's calculate the rate of Train A.
The relationship between the time and distance of Train A is given to us in a table.
Time (hr) | 2 | 3 | 4 | 5 | 6 |
---|---|---|---|---|---|
Distance (mi) | 50 | 75 | 100 | 125 | 150 |
Speed=Distance/Time To find the speed of Train A, we can take any pair of times and distances from the table and plug it into the formula.
Time (hr) | 2 | 3 | 4 | 5 | 6 |
---|---|---|---|---|---|
Distance (mi) | 50 | 75 | 100 | 125 | 150 |
Speed=Distance/Time | 50/2= 25 | 75/3= 25 | 100/4= 25 | 125/5= 25 | 150/6= 25 |
We can see that the speed of Train A is 25 miles per hour. Now, let's calculate the speed of Train B.
Observing Train B's graph of distance and time, we can see that the line passes through the point (1,20).
This means that the train traveled 20 miles in 1 hour. Also, we know that the speed of Train B is constant. Therefore, we can say that the speed of Train B is 20 miles per hour.
We found the rate at which each train is traveling.
Train | Speed (mph) |
---|---|
Train A | 25 |
Train B | 20 |
Train A is going at a faster rate than Train B.