Core Connections Integrated II, 2015
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Core Connections Integrated II, 2015 View details
2. Section 3.2
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Exercise 106 Page 192

Create a slope triangle with an angle of 25^(∘) and an adjacent side of 1 unit.

Equation: y≈ 0.47x+4
Sketch:

Practice makes perfect
To write the equation, we have to find its slope m and y-intercept b. When we know this we can write the equation in slope-intercept form. y= mx+ b In addition to the y-intercept we know the angle at which the line increases. Let's demonstrate this with a graph. Note that a line's slope is defined as the vertical change when you move 1 unit in the positive horizontal direction. Therefore, from the y-intercept we will also draw a slope triangle with a horizontal side of 1 and an angle of 25^(∘).
If we can find the value of m we can get the slope of the line. Since we know the adjacent leg to the given angle, by using the tangent ratio we can find the value of m.
tan θ = Opposite/Adjacent
tan 25^(∘) = m/1
Solve for m
tan 25^(∘) = m
m=tan 25^(∘)
m = 0.46630...
m ≈ 0.47
The slope is about 0.47. With this information we can complete the equation. y≈ 0.47x+4