Core Connections Integrated II, 2015
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Core Connections Integrated II, 2015 View details
2. Section 2.2
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Exercise 53 Page 99

The area of a triangle is half the product of its height and base.

h=5
Perimeter≈ 24.2

Practice makes perfect

The area of a triangle is half the product of its height and base. A=1/2bh From the exercise, we know that the area is 25 square feet. The base, which is perpendicular to the height, is the sum of the segments that's 6 and 4.

If we substitute the base and area into the formula, we can solve for its height.
A=1/2bh
25=1/2( 10)h
Solve for h
25=5h
5=h
h=5
The height is 5 inches. To find the perimeter, we also need to know the remaining two sides of the triangle, which we will label c and z. Notice that these sides are the hypotenuse of a right triangle which means we can use the Pythagorean Theorem to solve for these sides.
Let's solve for c in the first equation.
6^2+5^2=c^2
Solve for c
36+25=c^2
61=c^2
c^2=61
c=± sqrt(61)

c > 0

c=sqrt(61)
Let's solve for z in the second equation.
4^2+5^2=z^2
Solve for c
16+25=z^2
41=z^2
z^2=41
z=± sqrt(41)

c > 0

z=sqrt(41)
When we know all of the sides, we can calculate the perimeter by adding them. Note that the triangle's height is not a part of the triangle's perimeter. 6+4+sqrt(41)+sqrt(61)≈ 24.2