Core Connections Integrated I, 2013
CC
Core Connections Integrated I, 2013 View details
2. Section 8.2
Continue to next subchapter

Exercise 111 Page 479

In an exponential function on the form the coefficient shows the function's intercept, while is the function's multiplier. Examining the diagram, we can determine the intercept directly.

Now we have half of what we need to write the equation.
Finally, to find we have to substitute a point into the function that does not fall on either of the axis. From the diagram, we can identify such a point.
When we know one more point on the function, we can substitute it into the function and solve for
Now we can complete the equation.