Core Connections Geometry, 2013
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Core Connections Geometry, 2013 View details
1. Section 6.1
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Exercise 39 Page 360

Practice makes perfect
a To draw the tree diagram, we first need to determine the probability of her phone showing each type of photo. To calculate probability, we divide the number of favorable outcomes by the number of possible outcomes.

P=Number of favorable outcomes/Number of possible outcomes From the exercise, we know that 2 photos are of her parents, 1 is of her niece and 3 are of her boyfriend for a total of 6 photos. Now we can determine the probability of each type of photo showing up when she turns on the phone. P(parents)&=2/6 [0.8em] P(niece)&=1/6 [0.8em] P(boyfriend)&=3/6 When we know all probabilities, we can draw our tree diagram.

b Let's first highlight the path through the tree diagram that shows both pictures being of her boyfriend. To calculate the probability of two events both happening, we have to use the Multiplication Rule of Probability.
P(A and B)=P(A)* P(B) With this, we can calculate the probability that both pictures are of her boyfriend.

P(A and B)=P(A)* P(B)
P(both of boyfriend)= 3/6* 3/6
P(both of boyfriend)=9/36
P(both of boyfriend)=1/4

c Let's highlight the paths in the tree diagram where neither photo is of her niece.
To calculate each of these probabilities, we have to use the Multiplication Rule of Probability. P(parents,parents):& 2/6* 2/6=4/36 [0.8em] P(parents,boyfriend):& 2/6* 3/6=6/36 [0.8em] P(boyfriend,parents):& 3/6* 2/6=6/36 [0.8em] P(boyfriend,boyfriend):& 3/6* 3/6=9/36 By adding these probabilities, we get the probability that neither of the photos are of her niece

P(neither of niece)=4/36+6/36+6/36+9/36
P(neither of niece)=25/36
P(neither of niece)=5/6