Core Connections Geometry, 2013
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Core Connections Geometry, 2013 View details
1. Section 4.1
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Exercise 51 Page 233

Practice makes perfect
a To determine if the sequence is arithmetic or geometric, we have to find out if there is a common difference or a common ratio between consecutive terms.
We have a common ratio between consecutive terms which means this is a geometric sequence. The formula for a geometric sequence follows a certain format. a_n=a_0( b)^n In the formula, n is the term number, b is the common ratio and a_0 is the zeroth term. We have already determined that the common ratio is b= 12. Let's add this to the formula. a_n=a_0( 1/2)^n To find the zeroth term, we can, for example, substitute a_1= 12 in the formula and solve for a_0.
a_n=a_0(1/2)^n
a_1=a_0(1/2)^1
â–Ľ
Solve for a_0
a_1=a_0(1/2)
1/2=a_0(1/2)
1=a_0
a_0= 1
Now we can complete the equation. a_n=1(1/2)^n ⇔ a_n=(1/2)^n
b Like in Part A, we will first determine if this is a geometric or an arithmetic sequence.
We have a common difference between consecutive terms which means this is an arithmetic sequence. The formula for an arithmetic sequence follows a certain format. a_n= mn+a_0 In the formula, n is the term number, m is the common difference and a_0 is the zeroth term. We have determined that the common difference is m= - 2. a_n= - 2n+a_0 To find the zeroth term, we can, for example, substitute a_1=- 7.5 in the formula and solve for a_0.
a_n=- 2n+a_0
a_1=- 2( 1)+a_0
â–Ľ
Solve for a_0
a_1=- 2+a_0
- 7.5=- 2+a_0
- 5.5=a_0
a_0= - 5.5
Now, we can complete the equation. a_n=- 2n+(- 5.5) ⇔ a_n=- 2n-5.5