b Subtract Jacob's walking speed from the speed of the conveyor belt.
A
a 3 miles per hour
B
b 18 feet. See solution.
Practice makes perfect
a To determine speed we can use the following formula.
d=rtIn this equation d is distance, r is speed, and t is time. From the given information we know that the distance is d= 300 meters, the time Jung has is t= 60 seconds, and the conveyor belt travels at t= 2 miles per second. If we label the speed that Jung has to walk to make it to the terminal on time v, we can write the following equation.
300=(v+ 2)^(total speed) 60
Let's solve this equation for v.
Jung needs to walk with a speed of 3 miles per hour.
b From the exercise we know that the conveyor belt travels at 2 feet per second. If Jacob walks in the opposite direction with a speed of 1 foot per second, his final speed will be 2-1=1 foot per second in the direction the conveyor belt is traveling. With this information, we can determine how far he will travel.
