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Core Connections Algebra 1, 2013

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Core Connections Algebra 1, 2013 View details

2. Section 3.2

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Exercise 42 Page 108

Practice makes perfect

a To evaluate the expression, we substitute a= 23 in the expression and simplify.

24a

a= 2/3

24* 2/3

MoveLeftFacToNum

a*b/c= a* b/c

24*2/3

a/b=.a /3./.b /3.

8* 2

Multiply

16

b Again, we have to substitute a= 23 in the expression and simplify.

3a

a= 2/3

3* 2/3

MoveLeftFacToNum

a*b/c= a* b/c

3*2/3

Calculate quotient

2

c Note that this expression has a denominator of 0. However, we are not allowed to divide a by 0. Therefore, this expression is undefined.

d Before substituting, let's rewrite the expression somewhat.

0/a ⇔ 1/a* 0 Since any number multiplied by 0 has a product of 0, we do not even have to substitute the value of a, as it will always equal 0.

Subchapter links

3.2.1 Equations - Algebra Tiles p.107-108

3.2.2 Exploring an Area Model p.110-111

3.2.3 Multiplying Binomials and the Distributive Property p.114

3.2.4 Using Generic Rectangles to Multiply p.118