Core Connections Algebra 1, 2013
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Core Connections Algebra 1, 2013 View details
1. Section 1.1
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Exercise 5 Page 6

a The absolute value of a number is the distance between that number and 0 on a number line. We can use a number line to visualize this distance.

From the number line, we can see that |54|=54.

b To begin, we will focus on simplifying the absolute value. We can use a number line to determine |- 7 35| in the same way as in Part A.

From the number line, we can see that |- 7 35| is equal to 7 35. We can substitute this into the given expression and simplify. - |- 7 35| =- 7 35

c Let's begin by simplifying the individual absolute values using a number line. The absolute value of a number is the distance between this number and 0 on a number line.
From the number line, we can see that |3|=3 and |- 1|=1. We can substitute these values into the given expression and simplify.
|3| - |- 1|
3- 1
2
d Before we calculate the absolute value, we need to simplify the expression inside the absolute value.

|2.2-5.13| = |- 2.93| Now we can determine the absolute value using a number line. The absolute value of a number is the distance between this number and 0 on a number line.

As we can see, |2.2-5.13| is equal to 2.93.