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Core Connections Algebra 1, 2013

CC

Core Connections Algebra 1, 2013 View details

Chapter Closure

Exercise 88 Page 40

a To find f(4), we have to substitute x=4 into f(x)=-|x-7|+3 and evaluate.

f(x)=-|x-7|+3

x= 4

f( 4)=-| 4-7|+3

Subtract term

f(4)=-|-3|+3

|-3|=3

f(4)=-(3)+3

Remove parentheses

f(4)=-3+3

Add terms

f(4)=0

b Again, to find f(4), we substitute x=4 in f(x)= sqrt(x+12)4 and evaluate.

f(x)=sqrt(x+12)/4

x= 4

f( 4)=sqrt(4+12)/4

Add terms

f(4)=sqrt(16)/4

Calculate root

f(4)=4/4

Calculate quotient

f(4)=1

c Similar to above, we will substitute x=4 into the given rule.

f(x)=2-sqrt(x+23)

x= 4

f( 4)=2-sqrt(4+23)

Add terms

f(4)=2-sqrt(27)

Calculate root

f(4)=2-3

Subtract term

f(4)=-1

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