Exercise 89 Page 40

a Before we try to simplify the expression, recall that the absolute value is a distance on a number line between a number and 0. Therefore, it is always positive, because distance cannot be a negative value.

2÷|3-4|

SubTerm

Subtract term

2÷|-1|

AbsNeg

|-1|=1

2÷ 1

CalcQuot

Calculate quotient

b Keep in mind that absolute value is always positive number, and follow the order of operations.

11|-6|+15

AbsNeg

|-6|=6

11*6+15

Multiply

66+15

AddTerms

Add terms

c To find a cube root, think which number when you multiply it 3 times by itself will be equal to -8.

-19+sqrt(-8)

▼

Calculate root

Rewrite

Rewrite -8 as (-2)*(-2)*(-2)

-19+sqrt((-2)*(-2)*(-2))

ProdToPowThreeFac

a* a* a=a^3

-19+sqrt((-2)^3)

RootPowToNumber

sqrt(a^n)=a

-19+(-2)

AddNeg

a+(- b)=a-b

-19-2

SubTerm

Subtract term

-21

d This time, we need to find a square root. Think of what number multiplied by itself will give you 16.

-11-sqrt(16)

▼

Calculate root

Rewrite

Rewrite 16 as 4*4

-11-sqrt(4*4)

ProdToPowTwoFac

a* a=a^2

-11-sqrt(4^2)

RootPowToNumber

sqrt(a^n)=a

-11-4

SubTerm

Subtract term

-15

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Exercise 89 Page 40

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