Calculating Volumes of Solids

Concept

Volume

The volume of a solid is a measure of how much space it occupies in three dimensions. Meaning, it is the three-dimensional equivalent of area. Volume is measured using cubic units, such as cubic meters, m

^{3} .

Rule

Cavalieri's Principle

Cavalieri's principle states that two solids with the same height and the same cross-sectional area at every height have the same volume. This means, for instance, that skewed versions of the same solid have the same volume, so long as their heights are equal.

Rule

Volume Formulas

The volume of a solid can be calculated with a formula that depends on the solid's shape.

Rule

Prism

The volume of a prism is given by multiplying the area of its base, $B,$ with its height, $h .$ $V = B h$

Rule

Pyramid

The volume of a pyramid is a third of the volume of a prism with the same base. Thus, the formula for the pyramid's volume is: $V = \frac{B h}{3} .$

Rule

Cylinder

A cylinder has a base of a circle. Therefore, the cylinder's volume is calculated by multiplying the area of the circle with the height of the cylinder.

V = π r^{2} h

Proof

Volume of a Cylinder

Proof

Volume of a Cylinder

The formula for the volume of a cylinder can be proven by placing a rectangular prism next to it.

Suppose the prism and the cylinder have the same base area and height.

Thus, Cavalieri's principle states that two solids with the same base area and height have the same volume. Since the volume of a prism is given by $V_{P} = B h,$ the volume of a cylinder can be calculated with the same formula. The base of a cylinder has the shape of a circle. Its area can be expressed as $B = π r^{2} .$ Therefore, the formula for the volume of a cylinder is $V_{C} = π r^{2} h .$

It applies to all cylinders because there is always a prism with the same base area and height.

Rule

Cone

The volume of a cone is a third of the volume of a cylinder with the same base. Since the cone's base is in the shape of a circle, the formula for the volume of the cone is:

V = \frac{π r ^{2} h}{3} .

Proof

Volume of a Cone

Proof

Volume of a Cone

The formula for the volume of a cone can be derived using a pyramid.

Assume, the pyramid and cone have the same height, $h,$ and that the pyramid has a square base, whose side length is twice the radius of the cone's base.

Since the cone's diameter is equal to the side length of the square, the cone will fit inside the pyramid.

The base of the cone is a circle that fits exactly in the base of the pyramid. By studying the figure from below, the ratio between the bases can be determined.

The area of the square is calculated by taking the square of the side length. Further, the area of the circle is given by the square of the radius times

π .

A_{S} = (2 r)^{2} A_{C} = π r^{2}

The ratio between the areas can now be calculated by dividing the area of the circle with the area of the square.

\frac{A _{C}}{A _{S}}

SubstituteExpressionsSubstitute expressions

\frac{π r ^{2}}{( 2 r ) ^{2}}

CalcPowCalculate power

\frac{π r ^{2}}{4 r ^{2}}

SimpQuotSimplify quotient

\frac{π}{4}

The ratio between the areas is

\frac{π}{4} .

This will be the case for all cross sections of the pyramid and cone. Therefore, Cavalieri's principle implies that the volume of the pyramid is equal to the volume of the cone scaled by the factor

\frac{π}{4} .

The formula for the volume of a pyramid is:

V_{P} = \frac{B h}{3} .

As mentioned previously, the base area for the pyramid is expressed as

B = (2 r)^{2} .

V_{P} = \frac{( 2 r ) ^{2} h}{3} .

By multiplying the volume of the pyramid with the scale factor, the formula for the volume of the cone can be found.

V_{C} = \frac{π}{4} \cdot \frac{( 2 r ) ^{2} h}{3}

CalcPowCalculate power

V_{C} = \frac{π}{4} \cdot \frac{4 r ^{2} h}{3}

MultFracMultiply fractions

V_{C} = \frac{4 \cdot π r ^{2} h}{4 \cdot 3}

SimpQuotSimplify quotient

V_{C} = \frac{π r ^{2} h}{3}

The result is the formula for the volume of a cone.

Rule

Sphere

A sphere is a perfectly round solid composed of many circles. The formula for the volume of the sphere is given by: $V = \frac{4 π r ^{3}}{3},$

where

r

is the radius of the largest circle in the sphere.

Concept

Composite Solid

A solid that is made up of more than one solid is called a composite solid. The individual solids can be combined either by adding or subtracting them from one another. For instance, a hemisphere — half a sphere — can be combined with a cone to make something that resembles a snow cone, or it could be used to hollow out a cylinder.

The volume of a composite solid is either the sum or difference between the volumes of the individual solids, whichever is applicable.

Find the volume of the composite solid

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Exercise

Find the volume of ice cream in the wafer cup.

Assume that the wafer is in the shape of a cone and that the ice cream above the wafer is a hemisphere.

Show Solution

Solution

The ice cream can be interpreted as a composite solid, a combination of a cone and a hemisphere.

Thus, the sum of the cone's volume and the hemisphere's volume will be the volume of the ice cream. Let's start with calculating the volume of the cone.

Theory

Volume of the Cone

The volume of a cone can be calculated with the formula $V = \frac{B h}{3},$ where $B$ is the area of the base and $h$ is the height. The base of a cone is in the shape of a circle, Its area can be calculated using $B = π r^{2} .$ The radius of the base is the same as for the hemisphere, since it fits exactly with the cone.

The height of the cone is

4

inch and the radius is

1

inch. By substituting the known values, the volume of the cone can be calculated.

V = \frac{B h}{3}

Substitute

B = π r^{2}

V = \frac{π r ^{2} \cdot h}{3}

SubstituteValuesSubstitute values

V = \frac{π \cdot 1 ^{2} \cdot 4}{3}

Evaluate right-hand side

BaseOne

1^{a} = 1

V = \frac{π \cdot 1 \cdot 4}{3}

MultByOne

a \cdot 1 = a

V = \frac{4 π}{3}

The volume of the cone is

\frac{4 π}{3} in^{3}

.

Theory

Volume of the Hemisphere

A hemisphere is half of a sphere. Therefore, to calculate the volume we can use the formula for the volume of a sphere and multiply it by $\frac{1}{2} .$ $V = \frac{4 π r ^{3}}{3} \cdot \frac{1}{2} = \frac{4 π r ^{3}}{6}$ The formula requires the radius of the hemisphere, which is $1$ inch.

Now, the volume of the hemisphere can be calculated.

V = \frac{4 π r ^{3}}{6}

Substitute

r = 1

V = \frac{4 π \cdot 1 ^{3}}{6}

Evaluate right-hand side

BaseOne

1^{a} = 1

V = \frac{4 π \cdot 1}{6}

MultByOne

a \cdot 1 = a

V = \frac{4 π}{6}

SimpQuotSimplify quotient

V = \frac{2 π}{3}

Thus, the volume of the hemisphere is

\frac{2 π}{3} in^{3} .

Theory

Volume of the Composite Solid

The volume of the composite solid can be found by adding the volume of the cone,

V_{C},

and the volume of the hemisphere,

V_{H} .

V = V_{C} + V_{H}

SubstituteII

V_{C} = \frac{4 π}{3}

,

V_{H} = \frac{2 π}{3}

V = \frac{4 π}{3} + \frac{2 π}{3}

Evaluate right-hand side

AddFracAdd fractions

V = \frac{4 π + 2 π}{3}

AddTermsAdd terms

V = \frac{6 π}{3}

SimpQuotSimplify quotient

V = 2 π

Therefore, the volume of ice cream in the wafer is

2 π in^{3} .

Proof

Proof

Example

Find the volume of the composite solid