Exercise 17 Page 8

To solve the equation, we have to isolate d on one side. Using the Subtraction Property of Equality, we will subtract 16 from both sides of the equation. This will eliminate the constant on the right-hand side of the equation and isolate d.

5/6=1/6+d

SubEqn

LHS-1/6=RHS-1/6

5/6-1/6=1/6+d-1/6

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Subtract fractions

CommutativePropAdd

Commutative Property of Addition

5/6-1/6=d+1/6-1/6

SubFrac

Subtract fractions

4/6=d

ReduceFrac

a/b=.a /2./.b /2.

2/3=d

RearrangeEqn

Rearrange equation

d=2/3

To check that this solution is correct, let's substitute d= 23 into the original equation and simplify.

5/6=1/6+d

Substitute

d= 2/3

5/6? =1/6+ 2/3

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Simplify right-hand side

ExpandFrac

a/b=a * 2/b * 2

5/6? =1/6+2* 2/3* 2

Multiply

Multiply

5/6? =1/6+4/6

AddFrac

Add fractions

5/6=5/6 ✓

Since the left-hand side and right-hand side are equal, d= 23 is the correct solution.