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Divide the trapezoid into three figures.
Use inverse operations to isolate h.
Use the formula obtained in Part B.
A=1/2h(b_1+b_2)
h=2A/b1+b2
6 cm
We are given a trapezoid.
We want to find a formula for the area A of the trapezoid. To do so, notice that we can divide the trapezoid into three figures: two triangles and one rectangle.
This means that we can calculate the area of each figure and then add them to obtain the area of the trapezoid. Let's do one at time!
Consider that the base of the triangle is equal to a_1 and the height is h.
Now, recall the formula for the area of a triangle. A_1= a_1 * h/2
In this case, let's consider the base of the second triangle as a_2.
Again, we will use the known formula for the area of a triangle. A_2= a_2 * h/2
Finally, we will calculate the area of the rectangle. We can name the base b_1 and the height h.
Recall the formula for a rectangle. A_3= b_1 * h
Substitute expressions
Factor out h
a = 2* a/2
Write as a sum of fractions
Add fractions
a_1+a_2+b_1= b_2
Factor out 1/2
Commutative Property of Addition
LHS * 2=RHS* 2
a * 1/a=1
.LHS /(b_1+b_2).=.RHS /(b_1+b_2).
Cross out common factors
Simplify quotient
Rearrange equation
Now, we will find the height h of the given trapezoid.
Substitute values
Add terms
Multiply
Calculate quotient