Exercise 6 Page 149

To solve the equation, we have to isolate h on one side. We start by combining like terms.

1.8 = 2.1h - 5.7 - 4.6h

CommutativePropAdd

Commutative Property of Addition

1.8 = 2.1h - 4.6h - 5.7

SubTerms

Subtract terms

1.8 = - 2.5h - 5.7

Next, we can use the Properties of Equality to isolate h.

1.8 = - 2.5h - 5.7

AddEqn

LHS+5.7=RHS+5.7

1.8 + 5.7 = - 2.5h - 5.7 + 5.7

AddTerms

Add terms

7.5 = - 2.5h

DivEqn

.LHS /- 2.5.=.RHS /- 2.5.

7.5/- 2.5 = - 2.5h/- 2.5

MoveNegDenomToFrac

Put minus sign in front of fraction

- 7.5/2.5 = - 2.5h/- 2.5

ExpandFrac

a/b=a * 10/b * 10

- 75/25 = - 25h/- 25

CalcQuot

Calculate quotient

- 3 = h

RearrangeEqn

Rearrange equation

h = - 3

To check that this solution is correct, let's substitute h = - 3 into the original equation and simplify.

1.8 = 2.1h - 5.7 - 4.6h

Substitute

h= - 3

1.8 ? = 2.1( - 3) - 5.7 - 4.6( - 3)

MultPosNeg

a(- b)=- a * b

1.8 ? = - 6.3 - 5.7 - 4.6(- 3)

MultNegNegOnePar

- a(- b)=a* b

1.8 ? = - 6.3 - 5.7 + 13.8

SubTerm

Subtract term

1.8 ? = - 12 + 13.8

AddTerms

Add terms

1.8 = 1.8 ✓

Since the left-hand side and right-hand side are equal, h = - 3 is the correct solution.

Hints

Check the answer

Practice exercises

Asses your skill