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Point-slope form is y-y_1=m(x-x_1).
f(x) = -1/2x-1
Equations in point-slope form follow a specific format.
y- y_1= m(x- x_1)
In this form, m is the slope of the line and ( x_1, y_1) is a point on the line. We are looking for a function with values f(- 2) = 0 and f(6) = - 4. This means that the linear function passes through two known points.
Substitute ( - 2, 0) & ( 6, - 4)
a-(- b)=a+b
Add and subtract terms
a/b=.a /4./.b /4.
Put minus sign in front of fraction
Now that we know the slope of the line is - 12, we can write the equation of the line in point-slope form. We can use either of the given points as (x_1,y_1) in our equation. Let's use ( - 2, 0).
Substitute values
a-(- b)=a+b
Distribute -1/2
Identity Property of Addition
We found a line y=- 12x-1, so the function we are asked for is f(x) = - 12x-1.